Exact name filter needs to be broader and provide instructions
In search records, if enter "Keith" in the First Names field, and DO NOT check match exact, I get all sorts of results, most of which are irrelevant.
If I enter "Keith" and check match exact I get only "Keith".
If I enter "Keith B" and check match exact I get only "Keith B".
If I enter "Keith Brundrett" and check match exact I get only "Keith Brundrett".
If I enter "Keith*" or "*Keith*"and check match exact I get everything that includes "Keith".
Since most users do not know about special characters, it would be better if the search provided the same results as "Keith*" but without the "*" or any other special character. If someone is searching for a name that includes "Keith" but does not know to use "*", their search will be limited.
Also provide a pop-up tutorial that explains how to use other special characters, such as "?"
Comments
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I'm quite okay about the way these "exact" searches currently function, but agree there should be mention on the search page about the use of wildcards. "Keith" isn't a good example from which to make an illustration, but "Brundrett" is better. This, like many names, could be subject to the use of more than one wildcard, e.g. BR*NDR*T *, which would allow for variant spellings involving different vowels and one or two of the letter "t" at the end.
Some websites suggest one wildcard to substitute for one character and another for two or more, but I find an asterisk works okay for all my searches.
In summary, I don't think there is a need for any change (FamilySearch has switched the "exact search" functionality around over the years), but definitely think the options for getting enhanced results (use of wildcards, etc.) should be shown on the search page itself, rather than hidden away in a "Help" article.
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"Exact" means exact. Broader is not exact.
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Re-reading my earlier post, it appears I am requesting the option of being able to enter multiple wildcards in one name. Just to confirm that I am aware the ability to do this already exists.
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