I have a problem with the data downloaded from Family Search to Legacy
There are two sisters who are shown to marry the same man, and then both produce exactly the same children.
Both sisters are shown to die in 1886, yet the children continue to be born.
Philip Poad was the father born 1813 Yorkshire, England UK MGKM-J1P
the sisters are:-
Amy Jane Poad LV6K- FZ J and Mary Ann Poad LVSK- FD 1. Both are shown to marry Charles Taylor, though there are no specific marriage details (place and dates)
Both people were added some years ago by channonpm. Have you tried contacting that person? Of course, as the records are 6 years old, you may not get a reply.
It seems clear that channonpm was uncertain who was correct.
A Rich Clifton has been adding information more recently. It is worth trying to contact him as well.
At the end of the day, you need to decide what is correct and amend the records appropriately.
If you are unsure how to do this feel free to post to Community again.0
Maggie Taylor, has a source for the 1901 Census, which lists her mother Amy ( Jane Poad) Taylor ( LV6K- FZ J) as 45. It is also on her mother's record.
There is also a Record Hint for the 1911 Census, that lists her and the children.
Her son, Arthur P Taylor, LKWM-8F2 is also listed on those Census. Arthur P Taylor, LKWM-8F2 and Arthur Poad Taylor LKWM-8N1, may be the same person, He is listed under Amy and Mary Ann, but Mary Ann has no sources. She likely died in 1886.
The children might need to be removed from her record. https://www.familysearch.org/en/help/helpcenter/article/how-do-i-correct-parent-child-relationships-in-family-tree
We wish you success in correcting the records for Amy Jane Poad and Mary Ann Poad.0
Many Thanks. I was just concerned, that others may be lead astray. And I didn't know how to inform Family Search, that the info I had received from them was "off"
There will be a huge amount of confusion soon as the locations of records are now deceptive in the UK.
Which will make researching ones family roots even more difficult.0