Is it possible to show a merge could be needed?
최고 답변
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While we agree that this would be helpful, the problem is that making a check for possible duplicates for a single person is already a very expensive operation. Performing the check for everyone in the pedigree would be prohibitively expensive, and would also significantly slow down every view of a pedigree.
This is generally the reasoning involved whenever there is a mismatch between various views in the application. There are likewise some pedigree-specific hints that we calculate only when in a pedigree view and not on the person page, for the exact same reason. Sorry we can't make this happen (yet), but we appreciate you sharing your concerns.
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답변들
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You make a good point!
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